deskthority

If it's still possible: after I read the further discussion here in this thread, count me in for the Secret Santas please. I will find something nice.

Good to have you back Halvar!

7bit, run that script already!

Hooray! I'm deeply sorry if I scared you off earlier Halvar.

matt3o wrote: if your name appears twice in the list, you get two gifts?

This is an option‽ Well then, add me again!

Just please make sure that XMIT is not XMIT's Secret Santa.

If so, I think I'd give myself a beam spring, and in exchange, an Industrial M, since shipping would be so cheap.

Oh secret santa , i have been a good boy all year, may i please have a NIB SGI Bigfoot , the older one with the super thick PBT caps and the grey case. Thanks.

Oh and if you think i have been super good please include a SGI to USB converter. Thanks!!

This is the best I can do, but I'm no Santa!

http://deskthority.net/want-to-trade-f5 ... 11823.html

I asked 7bit to hold until the massive Surprise Box arrives here. (It's currently en route to me directly.) The Surprise Box has grown so much that I need to split it. Once I've had a look inside, I'll figure out if some of the contents can join in the Secret Santa instead. Bear with me! Shouldn't be more than a few days now.

Here comes the official list (sorted):
7bit
Compgeke
Halvar
HzFaq
JanitorJoe
Madhias
Muirium
Nuum
Ray
Redmaus
Spikebolt
XMIT
andrewjoy
chzel
gogusrl
guk
hypkx
jou
kbdfr
lolpes
matt3o
photekq
scottc
seebart
sethk
shrubbry
snoopy
webwit


There are 28 participants this year.


Everybody, please pm some permutations of degree 28 to The Keyboard Oracle.


The permutations should be in cycle notation, permuting the set {1,..,28}.
Only one permutation per line!

Example:
(1 5 18 13 9)(2 4 7 12)(3 6 27)(10 22 17 14)(14 21)
(1 2)(3 4)(5 6)(7 8)(27 28)


Except for the Keyboard Oracle, nobody will know the final order.

When the rolling deadline stopped rolling, the Keyboard Oracle will tell the bot those permutations. After applying them to the list, the bot sends out the addresses to each participant.

Remember: Matteo x2. I think someone else wants to do that as well. XMIT maybe?

I'm still waiting for this big ole box, mind.

7bit wrote: Everybody, please pm some permutations of degree 28 to The Keyboard Oracle.


The permutations should be in cycle notation, permuting the set {1,..,28}.
Only one permutation per line!

Example:
(1 5 18 13 9)(2 4 7 12)(3 6 27)(10 22 17 14)(14 21)
(1 2)(3 4)(5 6)(7 8)(27 28)

You lost me there...too late for coherent thinking...or math...

Alternatively, you can pm numbers between 1 and 304888344611713860501504000000 ...

Was about to ask if entering twice is actually possible. Now I doubt that I can manage to enter once correctly.
It has always been too late for math for me.

When it comes to mathematics tests, I always guess Zero. It's the most symmetric of all numbers.

chzel wrote:
You lost me there...too late for coherent thinking...or math...

Yeah me to :/ are we supposed to pm you any of the combinations? Can you please elaborate? Sorry kinda sleepy right now

Oooh… cool. As a DT mod I can see all the numbers show up at the Keyboard Oracle's inbox. (In fact, they show up in my email, whether I want to seek them out or not.) Let's cheat!

Anyway. We should wait until everyone's had a chance to decide how many Santas they want to have. Including the Surprise Box situation.

From the example earlier, it looks like 7bit will accept partial orbits, assuming the identity position for all elements not expressly named on a line.

As a concrete example, these are equivalent, with the former being a shorthand for the latter:
(1 2)(3 4)(5 6)(7 8)(27 28)
(1 2)(3 4)(5 6)(7 8)(27 28)(9)(10)(11)(12)(13)(14)(15)(16)(17)(18)(19)(20)(21)(22)(23)(24)(25)(26)

Wikipedia's article on this is garbage (edits welcome!) but Wolfram was more instructive:
http://mathworld.wolfram.com/PermutationCycle.html

I haven't yet convinced myself whether or not the permutations will yield the same result regardless of ordering.

Working on a PM...

(Oh, and I still want to be two Santas.)

See? It's easy for the US guys...it's evening over there...

7bit wrote: Alternatively, you can pm numbers between 1 and 304888344611713860501504000000 ...

Yes, but you'll still need a mapping from numbers to permutations.

is this one of those 7bit's midnight pranks or is this serious? not that I have problem creating a cyclic notation... but... why?!

7bit wrote: Everybody, please pm some permutations of degree 28 to The Keyboard Oracle.


The permutations should be in cycle notation, permuting the set {1,..,28}.
Only one permutation per line!

7bit, please PM me 27 volumes of 17th century Japanese poetry translated into Deutsch-Plattdeutsch within 7,77 minutes, or by 7am GMT. Please make the zip file to be exactly 7,7MB.

In base 7 ofcourse.

gogusrl wrote: In base 7 ofcourse.

Of course. And the hash value has to be exactly 7,77 to the 7th factor.

Can't we just use a 7-sided dice?

Muirium wrote: I asked 7bit to hold until the massive Surprise Box arrives here. (It's currently en route to me directly.) The Surprise Box has grown so much that I need to split it. Once I've had a look inside, I'll figure out if some of the contents can join in the Secret Santa instead. Bear with me! Shouldn't be more than a few days now.

I'm not sure this was (or rather: I'm sure this was not) intended by people who put things into the Surprise Box.
As for me, I'm taking part here because I expect a gift from a DT member playing Secret Santa (and of course want to play Secret Santa myself) and nothing else.

7bit wrote: […] There are 28 participants this year.


Everybody, please pm some permutations of degree 28 to The Keyboard Oracle.


The permutations should be in cycle notation, permuting the set {1,..,28}.
Only one permutation per line!

Example:
(1 5 18 13 9)(2 4 7 12)(3 6 27)(10 22 17 14)(14 21)
(1 2)(3 4)(5 6)(7 8)(27 28) […]

I first thought this was a joke. Reading the comments, I now think it was not.
But still I understand neither what 7bit expects nor the comments themselves.

OK, sorry.


I thought Group Theory is a commonly known field.


Just submit random numbers instead:
498367548937658943768543768954983675489376589437685437689544
6574832965784365784365748936543
5479360754983675489376589437685437689543768957438967548937658943


In a few days, the bot will evaluate them ...

My random number is 0. An infinite amount of calculation led to that sublime answer.

Kbdfr is quite right about the Surprise Box situation. No matter how bad it may be, I shouldn't mix up the two affairs. So let's just get on with this.

Has everyone decided how many Santas they will be yet? I'm sticking with 1. In Britain, you can't afford 2!

Maybe it is, but I never learned permutations that way, and although I understood reading the wiki, I would be afraid to send you and just screw up xD random number it is

Muirium wrote: My random number is 0. An infinite amount of calculation led to that sublime answer.

Kbdfr is quite right about the Surprise Box situation. No matter how bad it may be, I shouldn't mix up the two affairs. So let's just get on with this.

Has everyone decided how many Santas they will be yet? I'm sticking with 1. In Britain, you can't afford 2!

I think I can only do one, don't have enought to give away for 2, at least not things that I you guys may like, unless you want artisans in your sock the coal of DT gifts

Well, alternatively, I could make a script that generates random numbers between 1 and 28 without duplicates.


Just thought it would be more fun if everybody contributes randomness ...